All categories

3 years ago

How many positive integers are factors of 120 and also factors of 40?

Mathematics

1 answer:

olganol [36]3 years ago

6 0

Answer:

Step-by-step explanation:

The factors of 120 are:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 30, 40, 60, 120

The factors of 40 are:

1, 2, 4, 5, 8, 10, 20, 40

All you need to do is find the factors that both numbers share, which are:

1, 2, 4, 5, 8, 10, 20, 40

Count those, and you get 8

You might be interested in

Im so confused right now. how do I do this?

Sedbober [7]

Step-by-step explanation:

V= L×W×H
you only need to know one side to figure out the
volume of a cube
volume is in 3Dimensions
Multiple the sides in any order
which side you call length, width, or height doesn't matter

that's how you find the answer.

does that help?

6 0

3 years ago

Read 2 more answers

HELP!!!!PLS!!

chubhunter [2.5K]

Answer:

12 units

Step-by-step explanation:

(-7,-6)

if you reflect it over the x-axis then the second number would be changing

-6 the opposite is 6

(-7, 6)

from -6 to 6 is 12 jumps

12 units is the distance from the original point

4 0

3 years ago

39 divide (2+1) - 2 x (4+1)

Anvisha [2.4K]

Answer:

8-2x I think

Step-by-step explanation:

You would first divide 39 by 3, ( 2 + 1 = 3) and get 13.

You would next take 5 away from 13 and get 8.

Then you have your answer, because you cannot simplify it more because both the numbers do not have the same variable.

8 0

3 years ago

Read 2 more answers

Charmaine is fertilizing her garden. The garden is in the shape of a rectangle. Its length is 12 feet and its width is 10 feet.

Nana76 [90]

Answer:

4 bags

Step-by-step explanation:

lxw

12x10=120

30x4=120

l=length

w=width

6 0

3 years ago

Write the equation for the quadratic function in standard form

Ede4ka [16]

Answer:

$y=x^2+6x+7$

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

$y = a(x-h)^2+k$

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

$y=a(x--3)^2+-2\\y=a(x+3)^2-2$

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

$7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a$

The vertex form of the equation is $y=(x+3)^2-2$ .

To write in standard form, convert vertex form through the distributive property.

$y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7$

8 0

4 years ago