Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
desmos
Step-by-step explanation:
look up desmos. its a grphing calculator and it gives u all the awnsers. welcome bro
Answer:
<em>8</em><em>+</em><em>s</em><em>+</em><em>n</em>
Step-by-step explanation:
Add s to 8=8+s
and add 3 to result=8+s+3
Answer:
x = 2
Step-by-step explanation:
4x +4=12
-4. -4
4x.= 8
divide both saide by 4
x. = 2
Answer:
£1690
Step-by-step explanation:
Amount invested by Brian = £1300
rate of simple interest = 10%
To find money Brian will have after three years
He will have amount invested in bank and interest earned in three years from that amount.
Simple interest for any principal amount p is given by
SI = P*R * T /100
where SI is simple interest earned
T is time period for which simple interest is earned
R is rate of interest
Substituting value of P , R and T we have
SI = 1300*10* 3 /100 = 390
Therefor interest earned will be £390
Total money with Brian after three years = principal amount invested + interest earned in 3 years
= £1300 + £390 = £1690