Ask question

Ask question

All categories

3 years ago

8

Two common names for streets are Second Street and Main Street, with 15,969 streets bearing one of these names. There are 365 m

ore streets named Second Street than Main Street. How many streets bear each name?

1 answer:

Helga [31]3 years ago

6 0

8167 streets are named Second Street and 7802 streets are named Main Street.

Step-by-step explanation:

Given,

Total streets = 15969

Let,

x be the number of streets named as Second Streets

y be the number of streets named as Main Streets

According to given statement;

x+y=15969 Eqn 1

x = y+365 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$(y+365)+y=15969\\y+365+y=15969\\2y=15969-365\\2y=15604$

Dividing both sides by 2

$\frac{2y}{2}=\frac{15604}{2}\\y=7802$

Putting y=7802 in Eqn 2

$x=7802+365\\x=8167$

8167 streets are named Second Street and 7802 streets are named Main Street.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

You might be interested in

Write the equations for the graphs below (worth 5 points)

serg [7]

Answers:

10) y= 1/2x - 2
11) y= 2x + 3
12) y= 2/3x - 4

I found this by using y=mx+ b

3 0

2 years ago

Read 2 more answers

If x = 6, find the value of<br> a) X+4<br> b) 3x<br> c)

White raven [17]

A) 6+4 = 10

b) 3(6) = 18

7 0

3 years ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

a

$P(\= X \ge 51 ) =0.0062$

b

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

So

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

2 years ago

Is a parallelogram an equilateral?

Vladimir [108]

"A quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram."

4 0

3 years ago

Nine more than a number is seventy nine

tigry1 [53]

Answer:

70

Step-by-step explanation

79 - 9 =70

3 0

3 years ago

Read 2 more answers