Answer:
8
Step-by-step explanation:
If the area is 32 and the formula for area of a triangle is base * height / 2, and you have base = 8 and height = x and area = 32, this would be:
8 * x / 2 = 32
Now, solve:

Answer:
In the world of exponents, 4 is the number being raised by the exponent, which is 2.
Let's answer the first question:
If the base is 4, what is the value if the exponent is 2?
- The base is 4 and the exponent is 2. We would multiply 4 two times.

So, it would be 16.
Let's answer the second question:
What if the exponent is -2?
<u>This is the rule for negative exponents:</u>
Using this rule, we can solve
.

So, our answer for the 2nd question is 1/16.
<em>The discriminant must be zero.</em>
Step-by-step explanation:
A Perfect-Square Trinomial is given by the form:

The discriminant in the quadratic formula is:

So in order to get a perfect square,<em> the discriminant must be zero.</em>
<em></em>
<h2>
Learn more:</h2>
Discriminant: brainly.com/question/1537997
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Step-by-step explanation:
1. we have to write the system specifications as:
A(x,y) give us the meaning that the consule x can be accessed when y is in a faulty condition
∀y∃A(x,y)
2. B(x,y) shows that users email has sent a message, y. Which is in the archive. C(x) shows the email address of user x is retrievable
∀x∃y[B(x,y)→c(x)]
3. D(x,y) shows that x can detect breach y'' and we have E(z) that tells us there is a compromise of z
∀y∃xD(x,y)↔ ∃zE(z)
4. F(x,y,z)
Y and z are distinct point ends which x connects
We have,
∀y∀z∃x∃a[x ≠a →F(x,y,z)^F(a,y,z)
5. G(x,y)
X knowst the password of y' and H(x) means that we have x to be a system administrator
∀x[H(x)→∀yG(x,y)] ∃x[H(x)^∀yG(x,y)]
Answer:Angles A, B, and C form a triangle. The sum of the angle measurements of a triangle is 180°. So, I can find the measurement of angle C by subtracting the measurements of angle A and angle B from 180°.
Step-by-step explanation: