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eimsori [14]
3 years ago
8

Two common names for streets are Second Street and Main ​Street, with 15,969 streets bearing one of these names. There are 365 m

ore streets named Second Street than Main Street. How many streets bear each​ name?
Mathematics
1 answer:
Helga [31]3 years ago
6 0

8167 streets are named Second Street and 7802 streets are named Main Street.

Step-by-step explanation:

Given,

Total streets = 15969

Let,

x be the number of streets named as Second Streets

y be the number of streets named as Main Streets

According to given statement;

x+y=15969    Eqn 1

x = y+365     Eqn 2

Putting value of x from Eqn 2 in Eqn 1

(y+365)+y=15969\\y+365+y=15969\\2y=15969-365\\2y=15604

Dividing both sides by 2

\frac{2y}{2}=\frac{15604}{2}\\y=7802

Putting y=7802 in Eqn 2

x=7802+365\\x=8167

8167 streets are named Second Street and 7802 streets are named Main Street.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/12522674
  • brainly.com/question/12747564

#LearnwithBrainly

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zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

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Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

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Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 0.9

So

\mu = E(X) = np = 105*0.9 = 94.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 94.5}{3.07}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

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7 0
2 years ago
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Nata [24]

Answer:

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Step-by-step explanation:

That would be y + 5 = -2

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2 years ago
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Alina [70]

Step-by-step explanation:

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(-1, 3) : 2×(-1)² + 1 = 2×1 + 1 = 3

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Answer:

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Step-by-step explanation:

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