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Alecsey [184]
2 years ago
6

Brainliest to who answers :>

Mathematics
2 answers:
rusak2 [61]2 years ago
7 0

Answer:

L is not valid.

Step-by-step explanation:

For any triangle, the sum of the two legs must be greater than the hypotenuse. Otherwise the two legs would not be long enough to touch.

mr Goodwill [35]2 years ago
6 0

Answer:

L

Step-by-step explanation:

to add to the previous basically correct answer :

for a triangle the sum of any 2 sides must be greater than the third side (not just legs and Hypotenuse).

for all other options any combination of sum of 2 sides being bigger than the third side works.

but for L

2 + 5 = 7, which is smaller than the third side (8). so, this cannot be a triangle.

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What is -3-(-3) negative three minus -3
Vesna [10]
The answer would be 0


Reminder: when you see “-(-“ always think of plus sign “+.” (My teacher in middle school taught me that). So, -3+3 would be that the answer is 0.

4 0
3 years ago
What is an equation of the line in slope intercept form? M=2/3 and y intercept is (0,-3)
lana66690 [7]

Answer:

y= (2/3)x -3

Step-by-step explanation:

M is equal to the slope in y=mx+b form. And the y intercept is equal to (0, -3), therefore the b part of the formula is -3.

6 0
3 years ago
Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

4 0
3 years ago
How do I solve problem 1?
alexira [117]
You do 90-45 bc the whole angel must equal 90

4 0
3 years ago
Read 2 more answers
Solve for t. 3t 35=6
zhenek [66]

The answers 9. I took the test :)


3 0
3 years ago
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