Answer:
![\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7B1%7D%7B12%7D%5Be%5E0%20-0%5D%3D%20%5Cfrac%7B1%7D%7B12%7D)
Step-by-step explanation:
Assuming this integral:
We can do this as the first step:
Now we can solve the integral and we got:
![\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7Be%5E%7B60x%7D%7D%7B12%7D%5CBig%7C_%7B-%5Cinfty%7D%5E0%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Be%5E%7B60%2A0%7D%20-e%5E%7B-%5Cinfty%7D%5D)
So then we see that the integral on this case converges amd the values is 1/12 on this case.
Answer: 20 degrees
Step-by-step explanation:
- You add both angle for them to equal 180
- You solve for x
- 3x-10=20; 6x+100=120
Answer:
there must be at least two lines on any plane because a plane is defined by 3 non-collinear points. Explanation: ... These lines may or may not intersect. If two of the 3 points are collinear, then we have a line through those 2 points as well as a line through the 3rd point.
X^2 - 1 = 0
x^2 -1^2 = 0
(x + 1) (x - 1) = 0
x + 1 = 0 or x - 1 = 0
x = -1 or x = 1
Ans: -1 and 1
