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3 years ago

The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.

Mathematics

1 answer:

polet [3.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

Pythagorean theorem: In a right angle triangle, the square of hypotenuse is equal to the sum of squares of other two sides

BC² + AB² = AC²

5² + AB² = 13²

25 + AB² = 169

AB² = 169 - 25

AB² = 144

AB = √144 = √12*12

AB = 12cm

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Topic integers<br> please solve this question <br> urgent

miskamm [114]

Given:

i) 3, -5, -2, 1

ii) -1, -8, -7, -2

iii) -2, -4, 0, 2

To find:

increasing order of the given numbers.

Solution:

Increasing order: We need to start from the smallest number, then write larger number and end with the largest number.

We know that all negative numbers are less than the positive numbers and larger negative value is always the smaller one.

For example: -3 is less than -1.

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ii) We have,

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3 years ago

Which triangles could not be similar to triangle ABC ? triangle a b c where angle b is a right angle. side a b is 15 cm. side b

STALIN [3.7K]

Answer:

option (b) and (d) are correct.

Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

and Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

Step-by-step explanation:

Given : triangle a b c where angle b is a right angle. side a b is 15 cm. side b c is 8 cm. side a c is 17 cm.

We have to select triangle from given options that are similar to ΔABC,

Two triangles are said to be similar when their corresponding sides are in same ratios and their corresponding angles are equal.

Consider : Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

FINDING CORRESPONDING RATIOS,

$\frac{AB}{JK}=\frac{15}{60}=\frac{1}{4}$

$\frac{BC}{KL}=\frac{8}{32}=\frac{1}{4}$

$\frac{AC}{JL}=\frac{17}{68}=\frac{1}{4}$

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔJKL

Consider : Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

FINDING CORRESPONDING RATIOS,

$\frac{AB}{DE}=\frac{15}{22.5}=\frac{2}{3}$

$\frac{BC}{EF}=\frac{8}{12}=\frac{2}{3}$

$\frac{AC}{DF}=\frac{17}{25.5}=\frac{2}{3}$

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔDEF

Thus, option (b) and (d) are correct.

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Answer:

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