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Tom [10]
2 years ago
8

Awad claims that when m is a negative integer and n is a positive integer, n-m is

Mathematics
1 answer:
Lelu [443]2 years ago
6 0

no ablo inglés solo español perdón por no responderte

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The equation of the line that contains the points (-8, 1) and (0, -5) is
posledela

Answer:

y = -3/4x -5 (G)

Step-by-step explanation:

Find the slope by using the slope formula. (It's hard to format here so look it up)

Basically, it is y2 - y1/x2 - x1

-5 - 1/ 0 + 8

-6/8 = -3/4

The slope is -3/4.

Plug in for y = mx + b

y (y coordinate) = -5

x (x coordinate) = 0

slope (m) = -3/4

-5 = -3/4(0) + b

-5 = 0 + b

b = -5

y = -3/4x -5

5 0
3 years ago
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
-x + 2y = 6 <br> * finding the slope and y intercept *
Aleonysh [2.5K]

Answer:

3

Step-by-step explanation:


3 0
3 years ago
HELPPPPPPPPP ME PLEASE????!!?!?!?!?!
Gnesinka [82]

Answer:

More than half

Step-by-step explanation:

Half is 0.5 this is 0.785 approximately 0.280 more or > 0.5

4 0
3 years ago
The graph of y = |2 is shifted to the left by 6 units.<br> What is the equation of the new graph?
Tasya [4]

Answer:

From your question, I am assuming you are talking about an absolute value graph. In this case the answer would be y = |2 + 6|

Step-by-step explanation: Always remember, when you are graphing absolute value graphs:

When you shift left or right, you put the amount you are shifting inside the absolute value sign.

When you are shifting up or down, you put the amount you are shifting outside the absolute value sign.

When shifting left on a graph, you usually think of subtraction. However, when dealing with absolute value graphs, when you are shifting left, you use addition, as you can see in this problem.

The same goes for right. You use subtraction when shifting right, contrary to what you may think.

However, when you go up, you still use addition, and when you shift down, you still use subtraction.

3 0
3 years ago
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