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nikitadnepr [17]
3 years ago
9

A mountain climber ascended 3 4 of a kilometer in 1 12 of an hour. What was the mountain climber’s ascent rate in kilometers per

hour?
Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0

A mountain climber ascended 3/4 of a kilometer in 1/12 of an hour. The mountain climber's ascent rate is ; C. 9 kilometers per hour.

Debora [2.8K]3 years ago
4 0
The mountain climber's ascent rate is calculated by dividing 3/4 kilometer by 1/12 of an hour. That is mathematically expressed as,
                                   ascent rate = (3/4 km) / (1/12 h) 
                                                     = 9 km/h
Thus, the climber ascended at a rate of 9 km/h. 
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Answer:

Solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

Step-by-step explanation:

We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.

<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>

Now, We check if our expressions are equivalent, by evaluating the expression for t=2.

If they are equivalent, they would have same result after evaluation.

First, put t=2 into 14t-3t

14t-3t\\Put\:t=2\\=14(2)-3(2)\\=28-6\\=22

Now put t=2, into 3t-14t

3t-14t\\Put\:t=2\\=3(2)-14(2)\\=6-28\\=-22\\

For solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

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B(a)   =  a              
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It's C
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Read 2 more answers
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