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nikitadnepr [17]
3 years ago
9

A mountain climber ascended 3 4 of a kilometer in 1 12 of an hour. What was the mountain climber’s ascent rate in kilometers per

hour?
Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0

A mountain climber ascended 3/4 of a kilometer in 1/12 of an hour. The mountain climber's ascent rate is ; C. 9 kilometers per hour.

Debora [2.8K]3 years ago
4 0
The mountain climber's ascent rate is calculated by dividing 3/4 kilometer by 1/12 of an hour. That is mathematically expressed as,
                                   ascent rate = (3/4 km) / (1/12 h) 
                                                     = 9 km/h
Thus, the climber ascended at a rate of 9 km/h. 
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Ierofanga [76]

Answer:

x = 23, and y = 27.

Step-by-step explanation:

Lets say,

x = width

y = length

this means,

x(2) + y(2) = 100

It also says that the width is 4 meters less than the length.

if we put that into equation form it would look like this,

y - 4 = x

using these 2 equations, we can use the subustusion method to find the x.

x(2) + y(2) = 100

turns in to this :

step 1.     (y - 4) (2) + y(2) = 100 - given

step 2.      2y -8 + 2y = 100 -  distribute

step 3.      4y -8 = 100 - Combine like terms

step 4.       4y  = 108 - Get rid of the 8

step 5        4y/4  = 108 /4 - divide

step 6 .          y = 27

So if y is 27, then

x(2)  +  27(2) = 100

x(2) + 54 = 100

100 - 54 = 46, so x(2) is 46, but to get x, we need to divide 46 by 2, since x multiplied by 2 equals 46.

46  / 2 = 23 = x

so x = 23, and y = 27.

and the rule that y - 4 = x still applies, since 27 - 4 = 23.

I hope this wasn't confusing! It did take a long time tho.

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