am sorry i thout this was my question not your answer sorry
Answer:
e = 30 V
Explanation:
given,
N = 30 turns
Area = 0.25 m²
angular speed = ω = 100 rad/s
Magnetic field = 0.04 T
maximum induced emf in the loop = ?
e = N B A ω
e = 30 x 0.04 x 0.25 x 100
e = 30 V
hence, the maximum emf induced in the loop is equal to e = 30 V
Answer:
The energy loss due to friction is 9465 J.
Explanation:
The given data :-
Mass of roller (m) = 500 kg.
The speed of roller coaster at height 27 m = 5.6 m/s.
Initial height of roller( h ) = 27 m.
The speed of roller coaster at bottom = 22 m/s.
Initial energy of roller at a height 27 m.
E₁ = K.E + P.E
E₁ =
=
= 7840 + 132435
E₁ = 140,275 J
The energy of roller at a height 2 m.
E₂ = K.E + P.E
E₂ =
=
= 121000 + 9810
E₂ = 130,810 J
The energy loss due to friction = E₁ - E₂ = 140,275 - 130,810 = 9465 J.
Answer:
![V(t)= 240V* H(t-5)](https://tex.z-dn.net/?f=V%28t%29%3D%20240V%2A%20H%28t-5%29)
Explanation:
The heaviside function is defined as:
![H(t) =1 \quad t\geq 0\\H(t) =0 \quad t](https://tex.z-dn.net/?f=H%28t%29%20%3D1%20%5Cquad%20t%5Cgeq%200%5C%5CH%28t%29%20%3D0%20%5Cquad%20t%20%3C0)
so we see that the Heaviside function "switches on" when
, and remains switched on when ![t>0](https://tex.z-dn.net/?f=t%3E0)
If we want our heaviside function to switch on when
, we need the argument to the heaviside function to be 0 when ![t=5](https://tex.z-dn.net/?f=t%3D5)
Thus we define a function f:
![f(t) = H(t-5)](https://tex.z-dn.net/?f=f%28t%29%20%3D%20H%28t-5%29)
The
term inside the heaviside function makes sure to displace the function 5 units to the right.
Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. (
when
, so it becomes just a 1, which we can safely ignore.)
Therefore our final result is:
![V(t)= 240V* H(t-5)](https://tex.z-dn.net/?f=V%28t%29%3D%20240V%2A%20H%28t-5%29)
I have made a sketch for you, and added it as attachment.
You have to draw a mathematical spatial axes .in order to judge is it right or not .. well you have to draw the crest and trough both of 1 cm in length and the total wavelength (same phase on the wave of 2 cm ) something like this