The product of (mass) x (acceleration) is equal to (force).
So if (force) doesn't change and (mass) changes, then
(acceleration) has to change in the other direction from (mass)
in order to keep their product constant.
If the (forces) on both wagons are equal but one wagon has
double the (mass) of the other, then the more massive wagon
has (1/double) = 1/2 the acceleration of the less massive one.
Draw an x y axis
3 miles west is 3 miles to the left, -3
4 miles south is 4 miles down, -4
connect the the point to the origin, that side is what you are looking for
that side is also hypotenus
using Pythagorean theorem
sqrt(-4^2 + 3^2)
sqrt(25)
5
your displacement is 5
Answer:
v = 1.15*10^{7} m/s
Explanation:
given data:
charge/ unit area
plate seperation = 1.69*10^{-2} m
we know that
electric field btwn the plates is
force acting on charge is F = q E
Work done by charge q id
this work done is converted into kinectic enerrgy
solving for v
v = 1.15*10^{7} m/s
Answer:
q2 = -1.61*10^-5 C.
Explanation:
It was given that,
F = 0.985N
q1 = +8.40 X10-6 C
q2 = ?
r = 1.11 m
k = 9 x 10^9 (standard)
It generally follows that, if force is attractive, charge will be negative.
force, F = kq1q2/r^2
0.985 = 9*10^9*8.40*10^-6*q2/1.11^2
75600q2 = 0.985*1.11^2
75600q2 = 1.2136
q2 = 1.2136/75600 = 1.60529
q2 = -1.61*10^-5 C.
