What is one other thing that needs to be controlled when testing the effect of particle size?

What breaks in the wires of an electric current?

atroni [7]

Explanation:

When the wires of a circuit will break, circuit will be open state and stop the flow of current. Once the wires are reconnected, current will start flowing again in the circuit.

7 0

3 years ago

Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out ov

Mumz [18]

Answer:

The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times(22\times10^{-2})^2}{1.5\times10^{-2}}$

$C=0.285\times10^{-10}\ F$

We need to calculate the potential

Using formula of potential

$V=Ed$

Put the value into the formula

$V=18000\times1.5\times10^{-2}\ V$

$V=270\ V$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=0.285\times10^{-10}\times270$

$Q=76.95\times10^{-10}\ C$

Here, the charge on both the positive and negative plates

$Q=+76.95\times10^{-10}\ C$

$Q=-76.95\times10^{-10}\ C$

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

$n=\dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{76.95\times10^{-10}}{1.6\times10^{-19}}$

$n=4.80\times10^{10}\ electrons$

Hence, The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

8 0

3 years ago

A 20 kg block rests on a rough horizontal table. A rope is attatched to the block and is pulled with a force of 80 N to the left

Pani-rosa [81]

Given :

Mass of block , M = 20 kg .

Force applied , F = 80 N .

Acceleration of block , $a=2.5\ m/s^2$ .

To Find :

The coefficient is Kinetic force friction between the block and the table .

Solution :

We know , Force equation on block is given by :

$F_{net }=F-\mu_k mg \\\\ma = F-\mu_k mg \\\\20\times 2.5 = 80 -\mu_k \times 20 \times 10\\\\\mu_k\times 200=30\\\\\mu_k=\dfrac{30}{200}\\\\\ mu_k=0.15$

Therefore , coefficient is Kinetic force friction between the block and the table is 0.15 .

Hence , this is the required solution .

5 0

4 years ago

A rocket engine provides 28,913 Newtons of thrust. The rocket has a mass of 2,350 kilograms. Calculate its acceleration if it mo

Dafna11 [192]

1. The unknown is acceleration
2. The givens are the force(28,913N) and the mass(2350kg)
3. The equation is a=f/m where a is acceleration,f is force and m is mass
4.a=28913/2350 a=12.30340426
5. Therefore its acceleration is 12.30m/s²(rounded to nearest hundredth)

6 0

3 years ago

In the human body oxygen is absorbed by the lungs and nutrients are absorbed by the small intestine in a single-cell organism th

Katyanochek1 [597]

<span>In a single cell organism, the absorption of nutrients and control of certain things to <span>come inside or go outside the cell directly involves the cell membrane. Although, the basic function of the cell membrane is to protect the cell from its surroundings. It also facilitates the transport of substances needed for survival.</span></span>

5 0

4 years ago