1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
e-lub [12.9K]
3 years ago
6

(a) For the sequence 11,13,15,17,............find the 13th term​

Mathematics
2 answers:
ziro4ka [17]3 years ago
5 0
I told you earlier the pattern is +2 why didn’t you just add it yourself lol
laila [671]3 years ago
3 0

Answer:

35

Step-by-step explanation:

the pattern is +2 so the answer is 35

You might be interested in
Point C has a _____ abscissa and a _____ ordinate.
bulgar [2K]

Abcissa is x, and ordinate is y.

In this case the x is positive, and the y is negative.

Therefore, the answer is "positive, negative"

8 0
3 years ago
Read 2 more answers
6. Rosanne is selling her Corvette. She wants to include a photo of her
Likurg_2 [28]

Answer:

add them

Step-by-step explanation:

you have to add them all up because it says find the range

6 0
2 years ago
3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0
2 years ago
by 14 1 4 each week for a number of weeks, w . He writes the expression 20(14) 20 ( 1 4 ) w to find the amount of radioactive su
erastovalidia [21]

Answer:

1/2 ^w : decay factor after w weeks

hope this helps

Step-by-step explanation:


8 0
3 years ago
This is confusing I need help pls
DIA [1.3K]

The answer to your question is 42

4 0
3 years ago
Other questions:
  • An airplane pilot can see the top of a traffic control tower at a 20 degree angle of depression. the airplane is 5,000 feet away
    14·2 answers
  • How is she wrong if she says it is a positive correlation because y is increasing
    14·1 answer
  • What is the line that is parallel to 2x-3y=1 ?
    9·1 answer
  • (08.01 MC)
    6·2 answers
  • Which of the following points is on the graph of y=x^2-4x+5 ?
    14·1 answer
  • An object that weighs 150 pounds on earth weighs only 56.55 pounds on Mars.The same object weighs only 24.9 pounds on the moon.
    6·1 answer
  • Write the fact family. for 6, 4, 24
    8·2 answers
  • The midpoint of a line segment with end points as (-10, y1) and (-6, 7) is (-8, 6). What is the value of y1?
    14·1 answer
  • The graph shows the amount of money Joe earns each hour he works. Which statement about the graph is not true?
    11·2 answers
  • What type of quadrilateral is DEFG? Select all that apply.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!