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dangina [55]
2 years ago
9

Point C has a _____ abscissa and a _____ ordinate.

Mathematics
2 answers:
bulgar [2K]2 years ago
8 0

Abcissa is x, and ordinate is y.

In this case the x is positive, and the y is negative.

Therefore, the answer is "positive, negative"

DedPeter [7]2 years ago
7 0
Positive , negative .
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Please help I'm very confused and frustrated.
Ray Of Light [21]

Step-by-step explanation:

-36.8 + 9.2(2). [as the value of x is 2]

-36.8 + 18.4

= - 18.4 [as the number with the

Negative sign is greater]

7 0
2 years ago
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The table below represents the displacement of a turtle from its nest as a function of time: Time (hours) x Displacement from ne
andriy [413]
Part A: The y-intercept is 5. If you look to the data, when x=0, y=5. This means that the turtle started off 5 miles away from its nest. (at 0 hours, the distance away from his nest was 5 miles)

Part B:Answer=22. Remember, if you take any two distinct points on a line, the slope of the line will be equal to the average rate of change. In short,  we're just looking for the slope between the ordered pairs (1,27) and (4,93). The formula for slope is:

slope= \frac{y_{2}- y_{1} }{ x_{2} - x_{1} } = \frac{93-27}{4-1}= \frac{66}{3}=22

The average rate of change between x=1 and x=4 is 22. The average rate of changed describes the rate at which miles is changing with respect the the change in hour.

Part C: Answer=10hours. Since by now we know both the slope and the y-intercept, lets write the equation in slope intercept form and then solve for 225 miles.

y=mx+b
y=22x+5
225=22x+5
subtract 5 from both sides
220=22x
divide both sides by 22
10=x
It would take 10 hours for the turtle to travel 225miles from it's nest.
4 0
3 years ago
Find the nonpermissiable replacelment for the variable in the expression. 3x/5x+2
Montano1993 [528]

Answer:

-2/5

Step-by-step explanation:

5 0
2 years ago
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If a cup of coffee has temperature 97°C in a room where the ambient air temperature is 25°C, then, according to Newton's Law o
FinnZ [79.3K]

Answer:

The  average temperature  is T_{a} = 81.95^oC

Step-by-step explanation:

From the question we are told that

    The temperature of the coffee after time t is   T(t) =  25 + 72 e^{[-\frac{t}{45} ]}

Now the average temperature during the first 22 minutes i.e fro 0 \to  22minutes is mathematically evaluated as

              T_{a} =  \frac{1}{22-0}  \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx

               T_{a} = \frac{1}{22} [25 t  +  72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.

             T_{a} = \frac{1}{22} [25 t  - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.

              T_{a} = \frac{1}{22} [25 (22)  - 3240e^{[-\frac{22}{45} ]}   - (- 3240e^{0} )]

            T_{a} = \frac{1}{22} [550  - 1987.12  +  3240]

          T_{a} = 81.95^oC

       

8 0
2 years ago
Whats the value of y help please
Aliun [14]

Answer:

25

Step-by-step explanation:

8 0
3 years ago
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