Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Answer:
______________the answer is Y=0.25X-3.25_______
Answer:
F(x) = 1/x^2
Step-by-step explanation:
F(x) = 1/x^2 is
y = 1/x^2
graph goes up to 10 each side
plug in 1,2,3,4,5,6,7,8,9,10 for x and see what y looks like
when x is 1,2,3,4,5,6,7,8,9,10
y is 1,1/4,1/9,etc
How does your figure look like?
Step-by-step explanation:
here's the answer to your question