take your compass on a point on your line. then draw a circle. take the 2 points in which the circle hit the line and draw 2 circles larger than half the distance between he 2 points. take the point that they intersect and and connect it to the line and you point M and it is purpendicular. does that make sense?
Answer:
To the nearest hundredth, this is 30.79 units
Step-by-step explanation:
To find the length of the arc, we simply apply the length of arc formula
Mathematically, that would be;
theta/360 * 2 * pi * r
Theta here is 98
r is 18 units
So the length of the arc will be;
98/360 * 2 * 22/7 * 18
= 30.7876 units
to the nearest hundredth, this is;
30.79 units
Answer:
85.56% probability that less than 6 of them have a high school diploma
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
50% of adult workers have a high school diploma.
This means that 
If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma
This is P(X < 6) when n = 8.

In which








85.56% probability that less than 6 of them have a high school diploma
Okay, to find length CE, your going to know the value of x. Length BC + CE = BD + DE.3x+47+x+26=27+x+10Simplify the equation to get4x+73=37+xyou can choose one of four ways to continue, but I will choose to subtract x3x+73=37Subtract 73 from both sides of the equal sign3x=-36divide by 3 on both sides of the equal sign to get the value of xx=-12Now, plug in -12 for x in length CE to get -12+26=14
(9-3)4
The cake had 24 pieces