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ValentinkaMS [17]
4 years ago
9

Help Please.. Can't figure it out

Mathematics
1 answer:
Alex787 [66]4 years ago
6 0

Answer:

The answer is option 3.

Step-by-step explanation:

The area of triangle formula is A = 1/2×base×height. Then substitute the following values into the formula :

area =  \frac{1}{2}  \times base \times height

Let base = 10,

Let height = 12,

area =  \frac{1}{2}  \times 10 \times 12

area  =  \frac{1}{2}  \times 120

area = 60 \:  \:  {m}^{2}

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Find the lateral area for the pyramid with the equilateral base.
Dafna11 [192]

Answer:

Option A is the correct answer.

Explanation:

 The given pyramid has 3 lateral triangular side as shown below.

 Base of triangle = 12 unit

 We need to find perpendicular.

  By Pythagoras theorem we have

            Perpendicular² = 10²-6²

           Perpendicular = 8 unit

So area of 1 lateral triangle = 1/2 x Base x Perpendicular.

                                             = 1/2 x 12 x 8 = 48 unit²

Area of lateral side = 3 x 48 = 144 unit²    

Option A is the correct answer.                

7 0
3 years ago
Read 2 more answers
SOMEBODY HELP PLEASEEE I DONT KNOW WHY THIS IS SUPPOSED TO BE 20+ CHARACTERS LONG BUT HERE IT IS
dimaraw [331]

<u>Answer:</u>

20h + 20

<u>Step-by-step explanation:</u>

5(2h + 4) + 10h

1️⃣ Expand by distributing terms.

<em>10h + 20 + 10h</em>

2️⃣ Collect like terms.

<em>(10h + 10h) + 20</em>

3️⃣ Simplify.

<em>20h + 20</em>

Answer: <em>20h + 20</em>

Done ✔

7 0
3 years ago
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A taxi charges $2.00 for the first mile and $1.60 for every additional mile. Rachel is taking a trip that is 4 miles long. How m
miss Akunina [59]
She should pay $6.80
7 0
3 years ago
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How to figure out this question: Jill is training for a marathon and runs 2 1/3 miles three times a week. How far will she run i
meriva
42 Miles in total
2 1/3 x 3 =7 
7 x 6=42

5 0
3 years ago
Which of the following statements is true for the logistic differential equation?
solong [7]

Answer:

All of the above

Step-by-step explanation:

dy/dt = y/3 (18 − y)

0 = y/3 (18 − y)

y = 0 or 18

d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)

d²y/dt² = dy/dt (-y/3 + 6 − y/3)

d²y/dt² = dy/dt (6 − 2y/3)

d²y/dt² = y/3 (18 − y) (6 − 2y/3)

0 = y/3 (18 − y) (6 − 2y/3)

y = 0, 9, 18

y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.

y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.

8 0
3 years ago
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