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stellarik [79]
2 years ago
5

Can someone help w/ d plz

Mathematics
1 answer:
asambeis [7]2 years ago
3 0

____________________________________________________

Answer:

\large\boxed{0}

____________________________________________________

Step-by-step explanation:

We are solving the expression: \frac{2*(3+(2-1))}{4-(6+2)} -(3-5)

Solve:

\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)\\\\\text{Lets start with the fraction}\\\\\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)\\\\\frac{2*(3+(1))}{4-(8)} -(3-5)\\\\\frac{2*(4)}{-4} -(3-5)\\\\\frac{8}{-4} -(3-5)\\\\-2 -(3-5)\\\\\text{Distrubute the negative to the numbers inside the parenthesis}\\\\-2 -3+5\\\\-5+5\\\\\boxed{0}

____________________________________________________

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