Question

Can someone help w/ d plz

Answer 1

____________________________________________________

Answer:

$\large\boxed{0}$

____________________________________________________

Step-by-step explanation:

We are solving the expression: $\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)$

Solve:

$\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)\\\\\text{Lets start with the fraction}\\\\\frac{2*(3+(2-1))}{4-(6+2)} -(3-5)\\\\\frac{2*(3+(1))}{4-(8)} -(3-5)\\\\\frac{2*(4)}{-4} -(3-5)\\\\\frac{8}{-4} -(3-5)\\\\-2 -(3-5)\\\\\text{Distrubute the negative to the numbers inside the parenthesis}\\\\-2 -3+5\\\\-5+5\\\\\boxed{0}$

____________________________________________________