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denis-greek [22]
3 years ago
8

What is the domain and range of f left parenthesis x right parenthesis= x2 + 4?

Mathematics
2 answers:
icang [17]3 years ago
7 0

Answer:

The domain is all real numbers or (-infinity, +infinity)

The range is all numbers greater than or equal to 4 or (4,+infinity)

Hope this helped! :)

fiasKO [112]3 years ago
3 0

ANSWER

(-∞,+∞)

EXPLANATION

The given function is

f(x) =  {x}^{2}  + 4

This is a polynomial function.

Polynomial functions are defined for all real values of x.

For every x-value, there is a corresponding y-value.

Therefore the domain of the given function is all real numbers.

We can rewrite this as:

(-∞,+∞).

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<span>If 5y*2=80 then y is equal to 8</span>
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The answer is C, but I don't understand why- can anyone tell me?
finlep [7]

Answer:

It's C because we are adding a number on the x but here we skip 5 so it's 6, and on y we add 4 up but since we skipped 5 we add 8 and we get 24. 6, 24. You may say "but SpiritBear, 17 plus eight is 25" and that is true, but if you notice the lowest dot actually starts on 5, not 4 making C right.

Hope this helped and wasn't too confusing

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2 years ago
In ΔUVW, the measure of ∠W=90°, VW = 32 feet, and WU = 78 feet. Find the measure of ∠V to the nearest degree.
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Answer: 67.68^{\circ}

Step-by-step explanation:

Given

\angle W=90^{\circ}

VW=32\ ft

WU=78\ ft

from the figure, we can write

\Rightarrow \tan v=\dfrac{UW}{VW}\\\\\Rightarrow \tan v=\dfrac{78}{32}\\\\\Rightarrow \tan v=2.437\\\Rightarrow v=\tan^-1(2.437)\\\Rightarrow v=67.68^{\circ}

7 0
3 years ago
A scale model of a city has a scale of 1 cm : 2.5 km. Two buildings in the model are 1.7 cm apart. To the nearest tenth of a kil
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This is the concept of linear proportionality, we are required to calculate the actual length between two buildings which have a distance of 1.7 cm when drawn to scale of 1 cm: 2.5 km. This can be calculated as follows;
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An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t
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Answer:

z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

\bar X=31.1 represent the sample mean  

\sigma=1.3 represent the population standard deviation

n=140 sample size  

\mu_o =31.3 represent the value that we want to test  

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:  

Null hypothesis:\mu =31.3  

Alternative hypothesis:\mu \neq 31.3  

Since we know the population deviation, the statistic is given by

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Replacing we got:

z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

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