Answer:
Hello
Here's the answer:
2x^2 + 5x + 2 = 0\\ 2x^2+4x+x+2=0\\ 2x(x+2)+1(x+2)=0\\ (2x+1)(x+2)=0\\ x=-\frac{1}{2} \vee x=-2
x^2-4x+1=0\\ x^2-4x+4-3=0\\ (x-2)^2=3\\ x-2 =\sqrt3 \vee x-2=-\sqrt3\\ x=2+\sqrt3 \vee x=2-\sqrt3
Step-by-step explanation:
I believe the following is your problem (if not do rectify me). If so, then:
⁵√x⁴ .⁵√x⁴
1st method:
⁵√x⁴ .⁵√x⁴ = x⁴/⁵ . x⁴/⁵ = x⁽⁴/⁵ +x⁴/⁵⁾ = x⁸/⁵ = ⁵√x⁸ = ⁵√(x⁵.x³) = x. ⁵√x³
2nd method:
⁵√x⁴ . ⁵√x⁴ = ⁵√(x⁴. x⁴) = ⁵√(x⁴⁺⁴) = ⁵√x⁸ = x .⁵√x³
<em><u>Answer:</u></em>
option A is the correct answer
Answer:
The y-intercept is 2
Step-by-step explanation:
Answer:
Step-by-step explanation:
a₁ = πr₁⁵ = 25π cm²
a₂ = 25(25π) = 625π cm²
r₂ = 25 cm
