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pav-90 [236]
3 years ago
13

Solve 1/2 + (- 3/4) =

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

-0.25 or 1/4

Step-by-step explanation:

Eh just know

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For 2 sweaters for that price what percent discount is that?
Harrizon [31]

Answer: 75% off


Step-by-step explanation:

Your first sweater is the full 100% of the cost. The second it only 50 percent. If you add these to find out how many percent you will pay which is 150 for both. If you were to divide by 2 you get 75 percent off each sweater. The first sweater is $48 the second you multiply by .5 (as its 50 percent off ) and the cost is $24 dollars. 48 plus 24 is 72 then that divided by 2 is 36. Now 36$ is the price per sweater.  36/48 or  3/4 (which is 75%)

6 0
3 years ago
Which measurements would be correct for trapezoid EFGH if it were similar to trapezoids ABCD?
grandymaker [24]
<span>C side EF=18 cm; side GH = 30 ; height = 6 cm </span>
5 0
3 years ago
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Which table in this photo shows a proportional relationship between X and Y?
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Your answer to this question is definitely C!
5 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
2 years ago
What is the common ratio for the geometric sequence?<br><br> 35/2, 7, 14/5, 28/25, ..…
LiRa [457]

Answer:

2/5

Step-by-step explanation:

8 0
2 years ago
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