Answer: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Step-by-step explanation:
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:
Since we have given that

Using the poisson process, we get that
(a) less than or equal to 12
probability= 
(b) equal to 13
probability=

(c) greater than 12
probability=

(d) equal to 20
probability=

(e) between 10 and 15, inclusively
probability=
Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318