Solve the equation for all degree solutions and if 0° ≤ θ < 360°. Do not use a calculator (Enter your answers as a comma-sepa rated list. If there is no solution, write no solution.) 1. 2 sin θ= root 2
(a) all degree solutions (let k be any integer.)
(b) 0≤ θ < 360°
2. 2 cos θ − root 3=0
(a) All degree solutions (let k be any integer.)
(b) 0≤ θ < 360°
3. root 3 cot θ- 1=0
(a) all degree solutions (Let k be any integer.)
(b) 0° ≤ θ < 360°
1 answer:
Answer:
1.-
a) θ = 45 ° + 360k
θ = 135° + 360k
b) θ = 45 ° 0 ≤ θ < 360°
θ = 135°
2.-
a) θ = 30° + 360k
θ = 330° + 360k
b) θ = 30° 0 ≤ θ < 360°
θ = 330°
3.-
a) θ = 60° + 360k
θ = 240° + 360k
b) θ = 60° 0 ≤ θ < 360°
θ = 240°
Step-by-step explanation:
1) 2 sin θ = √2
sin θ = √2/2
1.a ) θ = 45 ° + 360k
θ = 135° + 360k
1.b) θ = 45 ° 0 ≤ θ < 360°
θ = 135°
2.
2 cos θ - √3 = 0
2 cos θ = √3
cos θ = √3/2
2.a θ = 30° + 360k
θ = 330° + 360k
2.b θ = 30° 0 ≤ θ < 360°
θ = 330°
3.- √3 cot θ - 1 = 0
√3 cot θ = 1
cot θ = 1 /√3
3.a θ = 60° + 360k
θ = 240° + 360k
3.b θ = 60° 0 ≤ θ < 360°
θ = 240°
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