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Nitella [24]
3 years ago
10

What is the slope of a line that is parallel to the line whose equation is 0.5x-5y=9

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

0.5x - 5y = 9

<u>Make y the subject:</u>

5y = 0.5x - 9

y = 0.1x - 1.8

Match equation with y = mx + b

m = slope = 0.1

Parallel Slope = 0.1

Answer: The slope of the parallel line is 0.1

vovikov84 [41]3 years ago
3 0

The slopes of parallel line are the same.

We have: 0.5x - 5y = 9

Let's transform to slope-intercept form y = mx + b

0.5x - 5y = 9 |-0.5x

-5y = -0.5x + 9 |:(-5)

y = 0.1x - 1.8

Your answer is m = 0.1

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What is the value of 3 in 345,268.19
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3 is 300,000 in 345,268.19
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2 years ago
Tickets at the carnival cost 35 each.on Friday night the carnivals earned a total of 12,425 in ticket sales on Saturday night th
Blababa [14]

ticket sale on Saturday night is triple the ticket sale on Friday night.

Therefore

ticket sales on Saturday night = 3 x 12425 = 37275

Then

ticket sales for both nights = 12425 + 37275 = 49700

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\begin{gathered} 35n=49700 \\ \Rightarrow n=\frac{49700}{35}=1420 \end{gathered}

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6 0
8 months ago
Please help me answer these 2 questions with a FULL explanation so I know how to do the rest myself. Giving brainliest.
sveticcg [70]

Answer to 1:

\frac{x^3}{2y^25}

First thing you want to do is combine like terms on the bottom. Since it's multiplication, all you have to do is add the exponents. So for x you'd get x raised to the -9 power and for y you'd get 2y raised to the power of 7

Second thing is the numerator of the fraction. Since this is raising what is inside the paranthesis to a power, you must multiply this power by the powers of x and y, respectively. You should get x raised to the power of -6 and y raised to the power of -18

Here's where it gets complicated. to rationalize the problem, you must add parts from the numerator and denominator or vice versa. You cannot have any negative exponents anywhere in the fraction.  So that means for x you have to add 9 to the x on the top to cancel out the -6 and rationalize the remaining x's. You should end up with x^3.

For y, you work the opposite way. Since the negatives are only on the top, you simply add 18 to the bottom y's and it remains rationalized.

If done correctly this should come out to x^3/2y^25

Answer to 2:

(x^20y^12)/256

First thing you can do on this one is to cancel out the x^0s. Anything to the power of 0 equals one so only the coefficients will remain. Multiply those together and you'll get 4.

Next you will rationalize the ys. Add the bottom 3 to the top to cancel out the denominator and you're left with y^-3. Leave it like this for now.

Now is the difficult part. You must take everything that is inside the parenthesis to the power of -4. That includes the coefficients and the exponents. 4^-4 = 1/256. This means that you now must move the coefficients to the bottom. You should currently have y^-3/(256x^5).

Now take the exponents to the power using the same rules as question 1. -3*-4 = 12 and 5*-4 = -20. You should now have y^12/(256x^-20)

Lastly, we must rationalize the denominator. To do so, move the x^-20 to the numerator and make the exponent positive. After doing this, you have the answer: (x^20y^12)/256

3 0
2 years ago
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