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Nitella [24]
3 years ago
10

What is the slope of a line that is parallel to the line whose equation is 0.5x-5y=9

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

0.5x - 5y = 9

<u>Make y the subject:</u>

5y = 0.5x - 9

y = 0.1x - 1.8

Match equation with y = mx + b

m = slope = 0.1

Parallel Slope = 0.1

Answer: The slope of the parallel line is 0.1

vovikov84 [41]3 years ago
3 0

The slopes of parallel line are the same.

We have: 0.5x - 5y = 9

Let's transform to slope-intercept form y = mx + b

0.5x - 5y = 9 |-0.5x

-5y = -0.5x + 9 |:(-5)

y = 0.1x - 1.8

Your answer is m = 0.1

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Step-by-step explanation:

2c = -32

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7 0
2 years ago
A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If
jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

V=\frac{4}{3}\pi r^3, where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3

\text{Volume of one candle}=1766.25\text{ cm}^3

Now we will divide 70,650 cubic cm of wax by volume of one candle.

\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}

\text{Number of candles}=\frac{70,650}{1766.25}

\text{Number of candles}=40

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8 0
3 years ago
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A large explosion causes wood and metal debris to rise vertically into the air with an initial velocity of 96 feet per second. T
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Answer:

the height after 2 seconds will be 128 feet

Step-by-step explanation:

Data provided in the question:

Initial velocity = 96 feet per second

The function of height of falling debris above the ground is given as:

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A) To find height after time t = 2 seconds

substituting the value of time in the above function, we get

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or

h(t) = 192 - 64

or

h(t) = 128 feet

Hence,

the height after 2 seconds will be 128 feet

5 0
3 years ago
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