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ra1l [238]
3 years ago
7

If A=(B×C) and A is .85900249811274493513834238104686068217278974587753712238234187241537940938411357431027179824455466578260266

8739817984541093990334978416989938898961909783988032051954078868563923034098873197378700932482425938882174932235441340706357804758903520697054110365656200098892656093892519975646934730951300319670934148383930976486937991021107919634445096792852059368134348818516725092397897193965655010096668497110687246275781261416959036939948704519831131280227538350688368513198117381425216473246736979061305575805823776183580490720651098168584499732272163025287303466708130444964744364541833466147022888318355243001605870791782132732610566311510576714985737322465557714787156793292764660458544716982633485486029761. Then what is (B×C)
Mathematics
1 answer:
pogonyaev3 years ago
4 0

The 0's? mayve? because it could be possible that iit is 34

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At which price does quantity demanded equal quantity supplied?
yulyashka [42]

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3 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
Giving brainly answer quick noob
olga2289 [7]

Answer:

Ok

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
If (k-6)(k+2)-(k²-20)=2k+6, whatis tge value of k?​
xxMikexx [17]

K=1/3

simplify each bracket, put all numbers on the left hand side, equal it to 0 and solve for k

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2 years ago
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