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Nata [24]
3 years ago
13

Write an equation of the line that passes through (−3,7) and is perpendicular to the line y=−2x−5.

Mathematics
2 answers:
Murljashka [212]3 years ago
7 0

Answer:

Step-by-step explanation:

an equation is : Use the point-slope formula.

y - y_1 = m(x - x_1)    ;  m : the slope   when : x_1 = -3   and  y_1  = 7

- 2 ×m = - 1  because this line is perpendicular to the line y= -2x-5 when the slope is  -2

so : m= 1/2

an equation is : y - 7 =(1/2)(x+3)  

elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

The desired equation is

y = (1/2)x + 17/2

Step-by-step explanation:

The slope of the perpendicular line is the negative reciprocal of -2:  m = 1/2.

Start with y = mx + b.

Substituting 7 for y, 1/2 for m and -3 for x, we get:

                7 = (1/2)(-3) + b.  Then 7 = -3/2 + b, so that b = 17/2.

The desired equation is

y = (1/2)x + 17/2

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You can solve this by using the system of equations.
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Use elimination.
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Solve. And you'll get:
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Cross out -6H and 6H because they cancel out. And you're left with:
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Add -9C with 4C, and -14.85 with 10.9.
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Divide each side with -5.
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Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
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3 years ago
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