Question

Write an equation of the line that passes through (−3,7) and is perpendicular to the line y=−2x−5.

Answer 1

Answer:

Step-by-step explanation:

an equation is : Use the point-slope formula.

y - y_1 = m(x - x_1)    ;  m : the slope   when : x_1 = -3   and  y_1  = 7

- 2 ×m = - 1  because this line is perpendicular to the line y= -2x-5 when the slope is  -2

so : m= 1/2

an equation is : y - 7 =(1/2)(x+3)  

Answer 2

Answer:

The desired equation is

y = (1/2)x + 17/2

Step-by-step explanation:

The slope of the perpendicular line is the negative reciprocal of -2:  m = 1/2.

Start with y = mx + b.

Substituting 7 for y, 1/2 for m and -3 for x, we get:

                7 = (1/2)(-3) + b.  Then 7 = -3/2 + b, so that b = 17/2.

The desired equation is

y = (1/2)x + 17/2