Write an equation of the line that passes through (−3,7) and is perpendicular to the line y=−2x−5.
2 answers:
Answer:
Step-by-step explanation:
an equation is : Use the point-slope formula.
y - y_1 = m(x - x_1) ; m : the slope when : x_1 = -3 and y_1 = 7
- 2 ×m = - 1 because this line is perpendicular to the line y= -2x-5 when the slope is -2
so : m= 1/2
an equation is : y - 7 =(1/2)(x+3)
Answer:
The desired equation is
y = (1/2)x + 17/2
Step-by-step explanation:
The slope of the perpendicular line is the negative reciprocal of -2: m = 1/2.
Start with y = mx + b.
Substituting 7 for y, 1/2 for m and -3 for x, we get:
7 = (1/2)(-3) + b. Then 7 = -3/2 + b, so that b = 17/2.
The desired equation is
y = (1/2)x + 17/2
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Step-by-step explanation:
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Answer:
a) -4. -9. -2
-3. -5. -7
-8. -1. -6
b) -3. 4. -1
2 0 -2
1. -4 3
Step-by-step explanation:
a) -4. -9. -2
-3. -5. -7
-8. -1. -6
b) -3. 4. -1
2 0 -2
1. -4 3
