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No.
Half of 48 would be 24, not 21
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To determine the solution of the quadratic equation, use the quadratic formula which states that,
x = ((-b +/- sqrt (b² - 4ac)) / 2a
From the equation, a = 1, b = 14, and c = 112. Substituting these to the quadratic formula,
x = <span>((-14 +/- sqrt (14² - 4(1)(12)) / 2(1) = indeterminate
Thus, the equation does not a real number solution. </span>
Fractions not roots
Explanation
Just cuhz
Answer: D:
To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by 5. The solution to system B will be the same as the solution to system A.
Step-by-step explanation:
Answer:
okay
Step-by-step explanation:
