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Gnoma [55]
2 years ago
11

The perimeter of a rectangle is 24 cm. if the length is y cm, what is the width?

Mathematics
1 answer:
KiRa [710]2 years ago
3 0
Answer: x=12-y

2x+2y=24
2x=24-2y
x=12-y
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Plz help me I really need it ASAP
vekshin1

Answer:

32

Step-by-step explanation:

\frac{4ab}{8c}

\frac{4(8)(4)}{8(\frac{1}{2})}

\frac{4(32)}{4}

32

8 0
2 years ago
Read 2 more answers
Caren is making rice and beans. She can spend no more than $10 on the ingredients. Which situation is represented by the inequal
sergij07 [2.7K]
If you are given $10 every 3.5 hours and you want to find the unit rate per hour, you want to solve for how much money you make every hour. You do this by dividing the $10 by the 3.5 hours, which will result in about $2.86 per hour. (This is a rounded value)
5 0
3 years ago
-2 4/5 + 1/4 equals what ?
vlada-n [284]
Hey there! :)

Since 2 4/5 is greater than 1/4, the answer is negative.

You can just subtract 2 4/5 and 1/4 and add the (-) sign

2 4/5 - 1/4

Change the fractions so they can have a common denominator: 20

2 4/5 = 2 16/20

1/4 = 5/20

2 16/20 - 5/20 = 2 11/20

Add the (-) sign → -2 11/20

Answer ⇒ -2 11/20

:)
5 0
2 years ago
Find the distance between the points (3, 8) and (0,4).
Bingel [31]

Answer:

5

Step-by-step explanation:

(3,8) (0,4)

X1 = 3    X2 = 0

Y1 = 8    Y2 = 4

D=\sqrt{(X1-X2)^{2}+ (Y1-Y2)^{2}  }

D= \sqrt{(3-0)^{2} + (8-4)^{2} }

Do what's in the parentheses so...

  1. 3-0= 3
  2. 8-4= 4

Now plug it in!

D= \sqrt{(3)^{2}+(4)^{2}  }

Now you are going to finish the parentheses so...

  1. (3)^2= 9
  2. (4)^2= 16

Plug that in so that you have this...

\sqrt{9+16}

Add 9+16 to get...

\sqrt{25}

Then you are going to find the number or numbers that make this a perfect square...

\sqrt{25}= 5

So 5 is your answer

7 0
2 years ago
What is 8x-4y=-12;-3,-1,1 solve for y
polet [3.4K]
8x - 4y = -12
4y = 8x + 12
y = 8/4 x + 12/4
y = 2x + 3

When x = -3,
y = 2(-3) + 3 = -6 + 3 = -3
When x = -1,
y = 2(-1) + 3 = -2 + 3 = 1
When x = 1,
y = 2(1) + 3 = 2 + 3 = 5
3 0
3 years ago
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