Answer:
There are 6 classes we find the median by finding the middle number of the 3rd highest class and 4th highest class, even if this is a decimal.
6/3 = 3+ 0.5
The process would be different if some values are the same values already on the chart total of each class.
ie) 20 31 14 22 20 31
small data like this below you can rearrange
14 20 20 22 31 31
and see that 21 is the correct value
as there are even numbers, so we choose 20 , 22
and select the middle value = 21
Step-by-step explanation:
If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
To find the area, you have to multiply its height by its width.
Step-by-step explanation:
