So if boys is 6 and girls is 15 it would be 6/15, but that can be simplified to 2/5.
<span>Let the major axis = 2a , and the minor axis = 2b
∴ a = 26/2 = 13 and b = 24/2 = 12
and the equation of foci:
c² = a² - b²
= 13² - 12² = 169 - 144 = 25
∴ c = √25 = 5
∴ The distance between the foci = 2 * 5 = 10
</span>
Answer:
29%
Step-by-step explanation:
100%-71%=29%
Answer:
270
Step-by-step explanation:
For any arithmetic sequence
nth term is given by
nth term = a + (n-1)d
where a is first term,
d is common difference
d is given by nth term - (n-1)th term
sum of n terms given by
sum = n/2(2a + (n-1)d)
________________________________________________
Given arithmetic sequence
-2,0,2,4,6,8...
first term a = -2
lets take third term as nth term and second term as (n-1)th term to find common difference d.
d = 2 - 0 = 2
using a = -2 , d = 2, n = 18
thus, sum of first 18 terms = n/2(2a + (n-1)d)
=18/2( 2*(-2) + (18-1) 2)
=9 ( -4 + 34)
=9 ( 30) = 270
Thus, sum of first 18 terms is 270.
Answer:
Charlene cannot bring 20 books because the weight of her luggage will be more than the permitted weight. She can only bring at most 15 books
We can represent this inequality as:
5 + 3x ≤ 50
Step-by-step explanation:
Whenever we are dealing with inequalities, a good trick is to solve the problem using an "equals to" sign and change it to the "inequality" sign at the last minute.
Let us assume that she carries x books.
The weight of her suitcase + the weight of all the 3-pound books must not be more than 50 pounds.
We can represent this inequality as:
5 + 3x ≤ 50
having said this, to find the value of x, which is the maximum number of books she is allowed to carry.
To do this, we replace the inequality sign with the "equals to" sign
5 + 3x = 50
from this, we have that
3x = 45;
x = 45/3
x = 15 books
From this, we can see that Charlene is not allowed to carry more than 15 books.
i.e x ≤ 15
Charlene cannot bring 20 books because the weight of her luggage will be more than the permitted weight. She can only bring at most 15 books
