<span>These are five questions and five answers.
Part 1.] Identify the following series as arithmetic, geometric, both, or neither. Includes picture
Answer: arithmetic
Justification:
The arithmetic series are those in which the distance (difference) between any consecutive terms is constant, so you can find the term An adding the difference to the previous term, A(n-1).
In this case the series is:
∞
∑ (3 + na) =>
n=1
Term1: 3 + a
Term2: 3 + 2a
Term3: 3 + 3a
Term3: 3 + 4a
As you see, the difference between two consecutive terms is a, which shows that it is an arithmetic series.
Part 2.] Evaluate C(3, 3)
A.] 1
B.] 6
C.] 24<span>
Answer: option A) 1.
Explanation:
The formula for combinations is Cm,n = m! / [n! (m - n)! ]
So, for C3,3, C3,3 = 3! / [3! 0!] = 3! / 3! = 1.
From this you might learn that Cm,m for any m is always 1.
Part 3.] Evaluate C(6,3)
A.] 20
B.] 120
C.] 720
Answer: option A) 20
Explanation:
Use the same formula, Cm,n = m! / [n! (m - n)! ]
C6,3 = 6! / [3! 3! ] = 6*5*4 / (3*2*1) = 5*4 = 20
Part 4.] </span>How many subsets of four elements each exist in a set of seven elements?
A.] 4!
B.] C(7, 4)
C.] P(7, 4)
Answer: option B) C(7,4)
Explanation
You have to select collections of 4 elements from a set of 7 elements, and must realize that the order is irrelevant, i.e. it is the same the set ABCD as the set ACBD or DCAB or any combination of those four elements. So, the answer is a combination and not a permutation.
The number of subsets of 4 elements that you can form with 7 elements is: C(7,4), which is the option B.
Part 5.] What is the probability of having 3 children that are all boys?
A.] 1/2
B.] 1/8
C.] 3/8
Answer: option B: 1/8
Explanation:
The number of possible outcomes is 2 * 2 * 2 = 8
Only one of those outcomes is for all boys = 1
Therefore the probability is 1/8
You can see that representing the possible outcomes using B for boys and G for girls:
1) BBB (three boys)
2) BBG
3) BGB
4) BGG
5) GBB
6) GBG
7) GGB
8) GGG
Those are the 8 possible outcomes and as seen only one is for 3 boys.
</span>
Answer:
h < -2
Step-by-step explanation:
Answer:
FH = 108
Step-by-step explanation:
The given figure requires we use the Pythagorean theorem to write two relations involving right triangle side lengths. The Pythagorean theorem tells us the square of the hypotenuse is the sum of the squares of the other two sides.
__
<h3>Triangle EGH:</h3>
EG² = GH² +HE²
GH² = EG² -HE² = 53² -28² = 2025 . . . . . solve for GH², use given values
<h3>Triangle FGH:</h3>
FG² = GH² +FH²
FH² = FG² -GH² = 117² -2025 = 11664 . . . . solve for FH², use known values
FH = √11664 = 108 . . . . . take the square root
The length FH is 108.
Answer:
Step-by-step explanation:
dP/dh = kP
dP/P = k dh
ln P = kh + C
Now, using the points given,
ln 101.5 = C, so C = 4.62
ln 87.3 = k*1000 + 4.62
k = -0.00015
So, we have
ln P = -0.00015 h + ln 101.5
P = 101.5 e^(-0.00015h)
