Which line passes through the point (2, -1)

If y varies inversely as X and Y equals 5 when x equals 3 find X when Y is 15

omeli [17]

Answer:

x = 1

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 5 when x = 3

k = yx = 5 × 3 = 15, thus

y = $\frac{15}{x}$ ← equation of variation

When y = 15 then

15 = $\frac{15}{x}$ ( multiply both sides by x )

15x = 15 ( divide both sides by 15 )

x = 1

5 0

3 years ago

Help me please. i need to pass geometry

AleksandrR [38]

Answer:

1080°

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 8, thus

sum = 180° × 6 = 1080°

8 0

3 years ago

12 cm<br> 6 cm <br> What is the area of this

Ahat [919]

Answer:

If it's a rectangle, then:

12 x 6 = 72 cm²

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

a)

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

b)

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

c)

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$