Answer: 
Step-by-step explanation:
(3x^2+x-1)(x^4-2x+1)
=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1
=3x^6+x^5-x^4-6x^3+x^2+3x-1
Hope this helps!! :)
Please let me know if you have any question
Answer:
A
Step-by-step explanation:
Photomath, lol
Answer:
65.91078
Step-by-step explanation:
You add the two decimals, that gives you two decimals. Use those two decimals and place them to the right of the answer. =0)
32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze
<h3><u>
Solution:</u></h3>
From given,
Final mixture is 40 gallon
Let "x" be the gallon of 25 % antifreeze
Then, (40 - x) is the gallon of 50 % antifreeze
Therefore, according to question,
"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze
<h3><u>Therefore, we frame a equation as:</u></h3>
25 % of x + 50 % of (40 - x) = 30 % of 40
Solve for "x"

Thus, 32 gallons of 25 % antifreeze is used
Then, (40 - x) = (40 - 32) = 8
Thus 8 gallons of 50 % antifreeze is used
Answer:
48n-48
Step-by-step explanation:
I dont know the options but you just multiply
6 times 8n is 48n
6 times -8 is -48