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3 years ago

Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).

Mathematics

1 answer:

White raven [17]3 years ago

6 0

Answer:

A. y + 1 = -2(x – 5)

Step-by-step explanation:

For a line with slope m through point (h, k), the equation is ...

y -k = m(x -h)

Fill in your values of m=-2, h=5, k=-1 and you have ...

y -(-1) = -2(x -5)

y +1 = -2(x -5) . . . . . . simplify. Matches selection A.

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Which other expression has the same value as (-14) - (-8)? Explain your reasoning. *

Anarel [89]

Answer:

The answer is -22 because when you subtract -8 from -14 it gives you -22.

Hope this helps!

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2 years ago

Which statement is true about this question -4(2p+5)+8p=-11

aleksandrvk [35]

The answer to this problem is “C “

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2 years ago

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sergij07 [2.7K]

Answer:

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2 years ago

Write using algebra.<br><br> Jimmy ran m miles in t minutes. What was his speed?

Ilya [14]

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2 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

2 years ago