What is the simplified form of the expression 3²+7-y²-5-2y²-1

what is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? (1 point) y − 5

makkiz [27]

According to the question, the line is through the points $(0,5)$ and $(-2,11)$

To calculate the slope using standard formula that is :

$m = \frac{(y(2)-y(1))}{(x(2)-x(1))} = \frac{(11-5)}{(-2-0)} =\frac{6}{-2} = -3$

Now the slope equation will be: $m(x(2)-x(1)) = (y(2)-y(1))$

$y-5 =(-3)(x-0) = y = -3(x)+5$

The slope-intercept form is: $y = -3x+5$

What is the equation of the line?

To represent the set of points in an algebraic form is known as the equation of line. The set of points represent lines in the coordinate system. The parameters can be calculated and those parameters are slope and y-intercept.

To learn more about the equation of the line from the given link:

<u>brainly.com/question/14037984</u>

#SPJ4

5 0

11 months ago

Write 9− 16x⁴ as the product of two factors.

Marysya12 [62]

Answer:

The two factors will be $=(3+4x^2)\ and\ (3-4x^2)$

Step-by-step explanation:

We have given the equation $9-16x^4$

We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

As $9-16x^4$ can be written as $3^2-(4x^2)^2$ , as square of 3 is 9 and square of $4x^2$ is $16x^4$

So $9-16x^4=3^2-(4x^2)^=(3+4x^2)(3-4x^2)$

So the two factors will be $=(3+4x^2)\ and\ (3-4x^2)$

6 0

3 years ago

Larry Calanan has earnings of S518 in a week. He is single and claims 2 withholding allowances. His deductions include FICA, Med

qaws [65]

Answer:

$482

Step-by-step explanation:

Data provided:

Total earning per week = $518

Medicare, federal withholding, state disability insurance, state withholding, union dues = $15

charitable contributions = $21

Now,

The total deductions = $15 + $21 = $36

also,

Net pay = Total income - Total deductions

thus,

Net pay = $518 - $36

or

Net Pat = $482

3 0

2 years ago

Soft drink consumption in New Zealand. A survey commissioned by the Southern Cross Healthcare Group reported that 16% of New Zea

lidiya [134]

<h2>Answer with explanation:</h2>

Given : The proportion of New Zealanders consume five or more servings of soft drinks per week : $\hat{p}= 0.16$

a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006

b) Confidence interval for population proportion (p) :

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = Sample proportion.

n= Sample size.

z* = Critical value.

For n= 2006 , $\hat{p}= 0.16$ and critical value for 95% confidence interval : z* = 1.96

Then , the required confidence interval will be :

$0.16\pm (1.96)\sqrt{\dfrac{ 0.16(1- 0.16)}{2006}}$

$0.16\pm (1.96)\sqrt{ 0.000066999002991}$

$0.16\pm (1.96)(0.00818529186963)$

$0.16\pm 0.0160431720645$

$(0.16-0.0160431720645,\ 0.16+0.0160431720645)$

$(0.143956827935,\ 0.176043172064)\approx(0.144,\ 0.176)$

i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = $(0.144,\ 0.176)$