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Oxana [17]
3 years ago
7

Solve the two-step equation. -9x + 0.4 = 4 Which operation must be performed to move all the constants to the right side of the

equation? Then, which operation must be performed to isolate the variable? The solution to the equation is x = .
Mathematics
2 answers:
fomenos3 years ago
6 0

Answer:

x=-0.4

Step-by-step explanation:

We have the equation:

-9x+0.4=4

First, the operation to move all the constants to the right side is subtraction since we would have to subtract 0.4 from each side, let's see this:

-9x+0.4=4\\-9x+0.4-0.4=4-0.4\\-9x=3.6

Now, <u>we have all the constants on the right side of the equation.</u>

<u />

Now, the operation we need to perform to isolate the variable is division (since the x has a -9 that is being multiplied by x) we need to do the opposite operation:

-9x=3.6\\\frac{-9x}{-9} =\frac{3.6}{-9} \\x=-0.4

Thus, the answer to this equation is x= -0.4

Klio2033 [76]3 years ago
3 0

Answer:

a)

Subtract 0.4 from both side.

-9x +0.4 = 4

-9x + 0.4 - 0.4 = 4 - 0.4

-9x = 3.6

b)

divide by -9 both side

-9x/-9 = 3.6/-9

x = -0.4

Step-by-step explanation:

-9x+0.4=4

    -0.4  -0.4

_______________

-9x=3.6

__    __

-9     -9

________________

x=-0.4

AM really good !

Step-by-step explanation:

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(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

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A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
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