Question

4. A triangle plotted in the coordinate plane has vertices at (2, 3), (sqrt15,3) and (4,8). Which of the following

Answer 1

Answer:

Option(1) is the correct answer to the given question .

Step-by-step explanation:

let     $x1, y1=\ (2, 3)$

$(x2,y2)=(\sqrt{15,3} \ )$

$(x3,y3)=\ (4,8)$

Now we know that

$Area=\ \frac{1}{2} |x1(y2-y3)\ + \ x2(y3-y1)\ + x3(y1-y2)$

Now putting this value in the formula we get

$\frac{1}{2}|2(3-8)\ +\sqrt{15}(8-3)\ * 4(5-3)|$

$=\ \frac{1}{2}\ *9.3649$

=4.6824

Therefore option(1) is the correct answer .