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Rom4ik [11]
3 years ago
7

Determine if the two triangles are congruent. If they are, state how you know.

Mathematics
2 answers:
Llana [10]3 years ago
7 0

Answer:

SAS

Step-by-step explanation:

It tells you that there are two sides equal, and they both have a 90 degree angle. This means that they are congruent because of side, angle, side, or SAS.

Hope this is helpful!!

Y_Kistochka [10]3 years ago
4 0
They are congruent , one is just turned a little
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Omlll, I'm actually stuck rn xD If anyone can help,i'd appreciate it so much!! Tyssmm!!!!!
madam [21]

Answer: it’s acute

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the area of the kite. Round to the nearest tenth
LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

If the area equals p*q divided by 2 then your equation would look like this,

A= 2.4*16.4/2

A=39.36/2

A= 19.68‬ in^2

When rounded A=19.7 in^2

8 0
3 years ago
4x + 2(x - 5) - 3(2x -4)
Olegator [25]

Answer:

2

Step-by-step explanation:

Pull out like factors :

  2x - 4  =   2 • (x - 2)

(4x +  (2 • (x - 5))) -  6 • (x - 2)

 (4x +  2 • (x - 5)) -  6 • (x - 2)

Final Answer:

2

5 0
3 years ago
Given the sequence tn defined recursively below, find t4.
Alina [70]

Answer:

t_4 = 20

Step-by-step explanation:

The base case in the recursive function are:

t_1 = 1

t_2 = 2

The recursive case is equal to:

t_n = 2t_{n-1} + 3t_{n-2}

So replace t_n for t_4:

t_4 = 2t_{3} + 3t_{2}

In the new expression t_2 is a base case so you don't have to worry for that part, but t_3 is still the recursive case so evaluate again in t_n

t_3 = 2t_{2} + 3t_{1}

t_2 and t_1\\ are define as base cases so you replace for it's numbers:

t_3 = 2(2) + 3(1) = 7

Now return to t_4 and replace for the new values:

t_4 = 2(7) + 3(2) = 14 + 6 = 20

So the final answer is 20

3 0
3 years ago
E vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). The perimeter of ∆ABC is units, and its area is square units.
UNO [17]

We can use the distance formula to calculate perimeter: \sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2} = Distance


From A to B: √232

From B to C: 10

From C to A: √52


10 + √232 + √52 = 10 + 2√58 + 2√13


Perimeter = 10 + 2√58 + 2√13 units


For Area we can use matrices, but since one of the sides is horizontal, we can just calculate with distance formula and area of triangle formula.


The area of a triangle formula is 1/2(h x b)

h=height

b=base


So the height is 6 and the base is 16. (I graphed it.)

16 * 6 = 96 96/2 = 48 Area: 48 square units.

8 0
3 years ago
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