A=1/2(b1-b2)h Solve for h
1 answer:
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Answer:
or
(they're the same)
Step-by-step explanation:
- Simplify:
- Find a common denominator. The LCM of 6 and 5 is 30, so multiply the numerator and the denominator by the same thing: 6 × 5 = 30, -9 × 5 = -45, 5 × 6 = 30, 3 × 6 = 18
- Write the new fractions:
- Subtract: -45/30 - 18/30 =
I hope this helps!
Given: It is given that the length of the painting is 24 inches and the width is 11 inches.
To find: Area of the mat
Solution:
The watercolor painting is 24 inches long by 11 inches wide.
So, the area of the painting is:
The length of painting with mat is = 24 in + 3 in + 3 in = 30 in
The width of painting with mat = 11 in + 3 in + 3 in = 17 in
Now to calculate the area of mat subtracts the area of painting from the area of the mat.
Hence, the area of the mat is 246 in².