Another way to write this is 3(4+7)
Find the area of the parallelogram with vertices a(1,2,3), b(1,3,6), c(3,8,6), and d(3,7,3,)
Julli [10]
The answer is: <span>A=<span>√265</span></span>.
Answer:
C. $128
Step-by-step explanation:
320 x 0.5 = 160
320 - 160 = 160
160 x 0.20 = 32
160 - 32 = 128
Answer:
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We are given
Vertical asymptotes:
Firstly, we will factor numerator and denominator
we get

We can see that (x-3) is common in both numerator and denominator
so, we will only set x+3 to 0
and then we can find vertical asymptote


Hole:
We can see that (x-3) is common in both numerator and denominator
so, hole will be at x-3=0

Horizontal asymptote:
We can see that degree of numerator is 2
degree of denominator is also 2
for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator
and we get
y=1
now, we can draw graph
Graph: