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Nadya [2.5K]
3 years ago
7

Solve for x each is a parallelogram

Mathematics
1 answer:
jonny [76]3 years ago
3 0

Answer:

UW = EW+UE=2×EW because, EW=UE

7x-2=2×6= 12

7x=14

x=14/7

x=2

<h2>2 is the right answer.</h2>

x + 80 = 180 - (64 + 36)

x + 80 = 180 - 100

x + 80 = 80

x = 0

<h2>0 is the right answer.</h2>
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At 700 k, the rate constant for this reaction is 6.2 × 10–4 min–1. how many minutes are required for 10.0% of a sample of cyclop
Anna35 [415]

Answer:

170 min

Step-by-step explanation:

We know that there is a kinetics of the first order, which has the following equation:

ln ([A] t / [A] o) = -k * t

Solving for t:

t = - ln ([A] t / [A] o) / k

How we want to know is the time required with 10%, so [A] t / [A] o = 100% - 10%, that is, 90% = 0.9. We also know that k = 6.2 * (10 ^ -4)

Knowing this, we replace:

t = - ln (0.90) /6.2 * (10 ^ -4)

t = 170 min

Which means it will take 170 minutes.

8 0
3 years ago
A spherical ball just fits inside a cylindrical can that is 10 centimeters tall, with a diameter of 10 centimeters. Which expres
valentinak56 [21]

Check the picture below.

\bf \textit{volume of a sphere}\\\\ V = \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3} \\\\\\ V=\cfrac{500\pi }{3}\implies V\approx 523.6

3 0
3 years ago
Solve the formula for the given variable.<br> -2x + 6 = -3x<br> Help meee
borishaifa [10]

Answer:

x = -4

Step-by-step explanation:

I have a picture because Im bad at explaining

4 0
2 years ago
Read 2 more answers
What is the answer to this question that I<br> Don’t know?
valentinak56 [21]

Answer:

25

Step-by-step explanation:

so 9.9 ounce bag of takis

9.9/0.396=25

8 0
2 years ago
Use the method in the Example to find the square roots of 1 + √3i
kiruha [24]

Answer:

\sqrt{1 + \sqrt{3} i}=\pm (1.58+i 0.548)

Step-by-step explanation:

Given

z = 1 + √3 i

Let \sqrt{1+\sqrt(3) i}=p+iq

Squaring both sides

1+\sqrt(3) i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

1=p^2-q^2...........................(1)

comparing Im(LHS)=Im(RHS)

√3=2pq

q=\frac{\sqrt{3}}{2p}

Substitute q in equation (1)

1=p^2-(\frac{\sqrt{3}}{2p})^2

p^4-p^2-0.75=0

Let x=p^2

x^2-x-0.75=0

x=\dfrac{1\pm \sqrt{1^2+4\times 0.75}}{2}

x=\frac{1\pm 4}{2}

we take only Positive value because p^2=x

x=2.5  

p^2=2.5

thus p=\pm 1.58

q=\pm 0.548

thus,

\sqrt{1 + \sqrt{3} i}=\pm (1.58+i 0.548)

5 0
3 years ago
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