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inessss [21]
3 years ago
12

How many moles of MgCl2 are there in 342 g of the compound?

Chemistry
2 answers:
loris [4]3 years ago
6 0

<u>Answer: </u>

3.6 moles of MgCl_2 are present in 342 g of MgCl_2

<u>Explanation: </u>

Given the weight of compound MgCl_2  = 342 g

Atomic Mass of Mg = 24 amu

Atomic Mass of Cl = 35.5 amu

Computing the molar mass of MgCl_2  = (1 * 24)+(2 * 35.5)amu = 24 + 71 = 95 amu

No. of moles of a compound is calculated by the formula = \frac{\text { Weight }}{\text { Molar Mass }}

Substituting the value,

Moles = \frac{342}{95}=3.6 \mathrm{mol}

Therefore, 3.6 moles of MgCl_2  are present in 342 g of MgCl_2

Zanzabum3 years ago
4 0

Answer:

There are  342 g/ 95. 2 g/m = 3.59 moles

Explanation:

MgCl2 → Molar mass is 95.2g g/m

This is the mass in one mol so to find out the moles in 342g we have to divide the mass between the molar mass.

342 g/ 95. 2 g/m = 3.59 moles

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<h3>Further explanation</h3>

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