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viktelen [127]
3 years ago
12

You put scruffy can run up to 2 meters/sec on his fastest days scruffy has a mass of 8 KG what is his maximum kinetic energy on

his fastest days?
Chemistry
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

E = 16 J

Explanation:

We have,

You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg

It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :

E=\dfrac{1}{2}mv^2

Plugging all the values,

E=\dfrac{1}{2}\times 8\times 2^2 \\\\E=16\ J

So, the maximum kinetic energy on his fastest day is 16 J.

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Explanation:

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An element has a mass of 39.2 and an atomic number of 19. How many protons does this element have? How many neutrons? How many e
abruzzese [7]

Answer:

19 protons, 19 electrons, and 3 neutrons

Explanation:

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328. mL of 0.00345 M NaI (aq) is combined with 703. mL of 0.00802 M Pb(NO3)2 (aq). Determine if a precipitate will form given th
Vsevolod [243]

Answer:

The solution will not form a precipitate.

Explanation:

The Ksp of PbI₂ is:

PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)

Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>

When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:

[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>

[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>

<em />

Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>

If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.

Replacing:

Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹

As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.

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3 years ago
Two isotopes of the same element will have the same _____ but a different ____. (2 points)
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Two isotopes of the same element will have the same ATOMIC NUMBER but a different MASS NUMBER.

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