Answer:
The baby
Step-by-step explanation:
If you count the baby inside the pregnant woman, then he is the youngest.
1x1 = 1 !!
Hope this helped.
You must convert point slope form to standard form in this problem. point= (h,k)
POINT SLOPE:
y-(-1)=(3/4)(x-2)
y+1=(3/4)x-(3/2)
y= (3/4)x-(5/2)
Answer: x = 8
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I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)
log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2
Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.
Only x = 8 is a proper solution.
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You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)
So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed
<span>2a(5-b)=3b+7
<em>[open bracket]</em>
10a - 2ab = 3b + 7
<em>[solve for b, so we need to move all terms with b to the left]</em>
<em>[-3b on both sides]</em>
10a - 2ab - 3b = 3b + 7 - 3b
10a - 2ab - 3b = 7
<em>[move all those without b to the right]</em>
<em>[-10a on both side]</em>
10a - 2ab- 3b - 10a = 7 - 10a
-2ab - 3b = 7 - 10a
<em>[divide by -1 through to change b to be positive]</em>
2ab + 3b = 10a - 7
<em>[take b out as the common factor]</em>
</span>b(2a + 3) = 10a - 7<span>
<em>[divide by (2a+3) through]</em>
b = (10a -7)/(2a+3)
</span>
