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Rashid [163]
3 years ago
13

30 PTS Please make sure its easy to understand

Mathematics
1 answer:
arlik [135]3 years ago
4 0
1. -1/20
work: Write all numerators above the least common denominator: -8+2+5/20
*Calculate the sum or difference: -1/20
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-61 3/8 as a decimal number
Bezzdna [24]
-23.625 is the decimal number of -61 3/8
8 0
3 years ago
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mn(s) 2h (aq)→mn2 (aq) h2(g)mn(s) 2h (aq)→mn2 (aq) h2(g) express your answer in bolts using two decimal places.
Zielflug [23.3K]

The required Standard electrode potential is +1.18V.

What is Standard electrode potential?

  • The difference in voltage between the cathode and anode is known as the standard cell potential. View Cell Potentials for more details. All of the standard potentials are determined using 1 M solutions, 1 atm, and 298 K.
  • The difference between the two electrodes, known as the standard cell potential (Eocell), creates the cell's voltage.
  • The equilibrium potential can be measured using the standard electrode potential.
  • The potential of a cell under normal state circumstances, which are roughly represented by concentrations of 1 mole per litre, is known as the cell's standard state potential.

Given that,

Mn+2H^+-- > Mn^{+2}+ H_2

E°cell , E\°_{2H^+/H_2}-E\°_{Mn^+2/Mn}

0.0-(-1.18)=+1.18V

=+1.18V

The required Standard electrode potential is +1.18V.

Learn more about Standard electrode potential here:

brainly.com/question/14240930

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4 0
2 years ago
HELP ME ANSWER IT PLZ ASAP<br> 6(6x−1)=5(5x+4)−2x
mote1985 [20]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
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Please help! I'm leaving school and I have to teach myself this!
marusya05 [52]
She could actually miss and get a 0 because 108+72+95/3=91
5 0
3 years ago
What is the probability that a patient shows improvement
Alexeev081 [22]

Answer:

.3375

Explanation:

Total people who were given drug: 800

Total people who showed improvement: 270

Probability:

\boxed{ \sf \dfrac{favorable  \ outcomes }{total \  possible  \ outcomes}}

<em>insert values</em>

\rightarrow \sf \dfrac{270}{800}

<em>simplify</em>

<em />\rightarrow \sf \dfrac{27}{80}

<em>in decimals</em>

\rightarrow \sf 0.3375

3 0
2 years ago
Read 2 more answers
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