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3 years ago

What is the distance between (2.6) and (7,6)?

Mathematics

2 answers:

scZoUnD [109]3 years ago

6 0

Answer:

5 units

Step-by-step explanation:

(2,6) and (7,6)

Since the y coordinates are the same, we only need to look at the x coordinates

The distance between 2 and 7 is

7-2 =5

5 units

ivanzaharov [21]3 years ago

3 0

Answer:

5 units

Step-by-step explanation:

Since the y values are the same, they are already on the same vertical line. This means that we simply need to go horizontally in order to get the distance, which we could do two ways.

We could:

1.) Count the units on a graph

2.) Subtract the points to get our distance

The most simple and practical option would be 2, so when we subtract (7,6) from (2,6) we should get 5 units.

*Note*: you could also do it the other way around, and you would get -5, but of course, distance can't be negative so you would simply take the absolute value and still get 5

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Lorico [155]

Answer:

$17.50

Step-by-step explanation:

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2 years ago

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Strike441 [17]

Answer:

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Step-by-step explanation:

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4 years ago

A line contains the two points plotted in the coordinate plane below.

Andrew [12]

Answer:

The slope would be 3.

Step-by-step explanation:

The formula for finding slope is $\frac{y1-y2}{x1-x2}$
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2 years ago

True or false: (a) If A2 is defined then A is necessarily square. (b) If AB and BA are defined then A and Bare square. (c) If AB

andrew-mc [135]

(a) True. Suppose A is a not a square matrix, with m rows and n columns. Then A² is not defined, because you can't multiply an m×n matrix by another m×n matrix.

(b) False. As an example, consider the matrices

$A_{3\times2} = \begin{bmatrix}1&0\\0&1\\0&0\end{bmatrix}$

$B_{2\times3} = \begin{bmatrix}-1&0&1\\0&0&1\end{bmatrix}$

Then both AB and BA are defined, with

$AB_{3\times3} = \begin{bmatrix}-1&0&1\\0&0&1\\0&0&0\end{bmatrix}$

$BA_{2\times2} = \begin{bmatrix}-1&0\\0&0\end{bmatrix}$

In general, you can multiply any m×n by any n×m matrix.

(c) True. Multiplying a m×n matrix by a n×m matrix always yields a m×m matrix, and multiplying a n×m matrix by a m×n matrix always yields a n×n matrix.

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3 years ago