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Vladimir79 [104]
2 years ago
14

I WILL GIVE BRAINLY IF YOU ANSWER CORRECTLY AND NO LINKS

Mathematics
1 answer:
Setler [38]2 years ago
7 0

Answer:

1|5 means 15 Enter the answer in the box. … The given data set shows the distance traveled, in miles

Step-by-step explanation:

I think

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Lapatulllka [165]

I believe it's graph C! I hope it will help you...

5 0
2 years ago
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How many times greater is<br> 3.8 X 10^5 than<br> 1.9 X 10^2<br> 2<br> 20<br> 200<br> 2000
storchak [24]

Answer:

2 * 10^3 = 2000.

Step-by-step explanation:

3.8/1.9 * 10^5/10^2

= 2 * 10^3

6 0
2 years ago
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2-31. Write an equation and solve it to find the answer to the question below.  Use the 5-D Process to help you write the equati
raketka [301]

r = 25+b

n = 3b

n+r+b=435

3b+25+b+b=435

5b+25=435

5b=210

b=42

r = 25+42 = 67

n = 3(42) = 126

6 0
3 years ago
Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
(9/2+5/2)÷11/2÷1/5 please show work
Llana [10]
9/2 + 5/2
11/2
1/5
Answer: 70/11 (<span>6.363636)</span>
5 0
2 years ago
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