Answer:
Challenge-Handshake Authentication Protocol (CHAP).
Explanation:
In Computer technology, authentication can be defined as the process of verifying the identity of an individual or electronic device. Authentication work based on the principle (framework) of matching an incoming request from a user or electronic device to a set of uniquely defined credentials.
Basically, authentication ensures a user is truly who he or she claims to be, as well as confirm that an electronic device is valid through the process of verification.
In this scenario, an organization wants to implement a remote dial-in server to ensure that personnel can connect to the organization's network from remote locations. The authentication protocol must include encryption to prevent hackers from accessing the network.
Hence, the protocol which should be used is Challenge-Handshake Authentication Protocol (CHAP).
A Challenge-Handshake Authentication Protocol (CHAP) can be defined as a standard network access control protocol in which a client program dials in to a network access server to receive a random value and identification number that can only be used once.
Answer:C)Defeated the two most successful human Jeopardy! champions in a three-game match.
Explanation: Watson emerged from the IBM supercomputer made by Thomas Watson .It is made from the two main component analytical software and the artificial intelligence which made it a optimal for the question-answer feature.
Watson defeated Ken Jennings and Brad Rutter(earlier successful contestants) in the program named Jeopardy by answering questions correctly and quickly in 2011.Other options are incorrect because it did not worked as the software engineer,humane genome or won crossword puzzle.Thus the correct option is option (c).
Software problem.
Assuming "Software" is one of the available answers.
Answer:
Check the explanation
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
what this means is that the size of nut is lesser than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
what this means is that the size of bolt is lesser than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
