Answer:
Computers
Explanation:
Thats why I'm looking thru new on this subject
Answer:
9 bits
Explanation:
We all recognize 1 K bytes as =1024 bytes.
And the storage medium used for program instructions are the non-volatile flash memories. The MCUs are always 8 bits, and a piece of the instructions revenues two or one 16-bit words. Besides we know program memory magnitude through the device name, and as an instance, the ATmega64x line emanates with 64KB of flash, and the ATmega32x line emanates with 32 KB. And there is nobody like off-chip program memory, and all of the codes that are being implemented by the AVR essentially be on the on-chip flash. However, this restraint is not ever applied to the AT94 FPSLIC AVR/FPGA chips. Also, you must know that AVR is a family of microcontrollers established by ATEL in 1996. It is a Harvard architecture type single-chip 8-bit RISC microcontroller. And it is supposed to be the first microcontroller which applied flash memory for storing the program They are heavily used in embedded systems.
1k byte = 1024 bytes, However, if the program instruction takes 16 bits.
And hence it only wishes 512.
Here and now 512 = 10^9, and henceforth you necessitate 9 bits at minimum.
excluding you can somehow paginate that (such as through one-bit pagination, you will be necessitating only 8 bits and so on.)
Therefore the answer here = 9 bits.
Answer:
CT = 470nF + 1000nF = 1470nF or 1.47μF
Explanation:
When capacitors are connected together in parallel the total or equivalent capacitance, CT in the circuit is equal to the sum of all the individual capacitors added together. This is because the top plate of capacitor, C1 is connected to the top plate of C2 which is connected to the top plate of C3 and so on. The same is also true of the capacitors bottom plates. Then it is the same as if the three sets of plates were touching each other and equal to one large single plate thereby increasing the effective plate area in m2.
Since capacitance, C is related to plate area ( C = ε(A/d) ) the capacitance value of the combination will also increase. Then the total capacitance value of the capacitors connected together in parallel is actually calculated by adding the plate area together. In other words, the total capacitance is equal to the sum of all the individual capacitance’s in parallel. You may have noticed that the total capacitance of parallel capacitors is found in the same way as the total resistance of series resistors.
The currents flowing through each capacitor and as we saw in the previous tutorial are related to the voltage.
Answer:
<em> C.</em><em> </em><em>system prototyping</em>
Explanation:
Prototyping produces a quickly constructed working version of the proposed information system.
Planning
↓
Analysis
↓
Design
↓
System prototyping
↓
Implementation
Answer:
step 1 install app step 2 add any extension if needed step 3 open app and strp 4 get to work
