Answer:
Step-by-step explanation:uywegfywieflwef
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Answer:
![f^{-1}(x) = \frac{x+8}{8}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7Bx%2B8%7D%7B8%7D)
Domain of f(x): All real values.
Range of f(x): All real values.
Domain of f -1(x): All real values.
Range of f -1(x): All real values
Step-by-step explanation:
We are given the following function:
![f(x) = 8x + 8](https://tex.z-dn.net/?f=f%28x%29%20%3D%208x%20%2B%208)
Since it is a line, we have that both the domain is the range is the real set.
Inverse function:
The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function.
Finding the inverse function:
Exchange x and y in the original function, and isolate y. So
Original
![y = 8x + 8](https://tex.z-dn.net/?f=y%20%3D%208x%20%2B%208)
Exchanging:
![x = 8y - 8](https://tex.z-dn.net/?f=x%20%3D%208y%20-%208)
Isolating y:
![8y = x + 8](https://tex.z-dn.net/?f=8y%20%3D%20x%20%2B%208)
![y = \frac{x+8}{8}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7Bx%2B8%7D%7B8%7D)
![f^{-1}(x) = \frac{x+8}{8}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7Bx%2B8%7D%7B8%7D)
Answer:
5x
Step-by-step explanation:
hope this helps