81 a² - 25 
is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)
Step-by-step explanation:
The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs
- a² - b² is a difference of two squares
- a² - b² = (a + b)(a - b)
∵ The binomial is 81 a² - 25
∵ 
= 9
∵ 
= a
∴ 
∵ 
= 5
∵ 
= z³
∴ 
- The two terms have square root
∵ The sign between them is (-)
∴ 81 a² - 25 is a difference of two squares
∵ Its factorization is two identical brackets with different
middle signs
∵ 81 a² = 9a × 9a
∵ 25 = 5z³ × 5z³
- The terms of the two brackets are 9a and 5z³
∴ 81 a² - 25 = (9a + 5z³)(9a - 5z³)
81 a² - 25 is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)
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Answer:
f(7)=10-14=-4
Answer=-4
Step-by-step explanation:
Good evening ,
Answer:
Circle 0 , 4 , 16
Step-by-step explanation:
→ 0 = 0²
→ 4 = 2²
→ 16 = 4²
:)
Answer:
10 number of checks.
Cost = $6
Step-by-step explanation:
Given that:
Fixed Charges of first bank = $5
Charges of first bank per check = $0.10
Fixed Charges of second bank = $4
Charges of second bank per check = $0.20
To find:
Number of checks such that the charges for the banks become the same?
Solution:
Let the number of checks = 
Cost for the first bank for checks = $5 + $0.10
Cost for the second bank for checks = $4 + $0.20
As per question statement, both the costs are the same.
Comparing the values:
So, for 10 number of checks the cost will be same.
The cost = 4 + 0.20 
10 = <em>$6</em>
